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2x^2+11x-34=-4
We move all terms to the left:
2x^2+11x-34-(-4)=0
We add all the numbers together, and all the variables
2x^2+11x-30=0
a = 2; b = 11; c = -30;
Δ = b2-4ac
Δ = 112-4·2·(-30)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-19}{2*2}=\frac{-30}{4} =-7+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+19}{2*2}=\frac{8}{4} =2 $
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